What is the sum from n=1 to infinity of (cos(1.6))^n ?

The sum from n=1 to infinity of (cos(1.6))^n is converges

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sum from n=1 to infinity of (cos(1.6))^n

n = 1 \sum \infty (cos (1.6))^{n}

converges

Solution steps

n = 1 \sum \infty (cos (1.6))^{n}

Simplify

cos (1.6) : - 0.02919 \dots

= n = 1 \sum \infty (- 0.02919 \dots)^{n}

Apply Series Ratio Test:

converges

= converges

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What is the sum from n=1 to infinity of (cos(1.6))^n ?
The sum from n=1 to infinity of (cos(1.6))^n is converges