What is the limit as x approaches 4 of 2*e^{2/(x-4)} ?

The limit as x approaches 4 of 2*e^{2/(x-4)} is diverges

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limit as x approaches 4 of 2*e^{2/(x-4)}

x \to 4 lim (2 \cdot e^{\frac{2}{x - 4}})

diverges

Solution steps

x \to 4 lim (2 e^{\frac{2}{x - 4}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (2 e^{\frac{2}{x - 4}}) = \infty

x \to 4 - lim (2 e^{\frac{2}{x - 4}}) = 0

= diverges

x \to 0 lim ((- 3) sin (7 x))

y^{^{''}} - 1 = 0

\int ln ∣ x ∣ \cdot 1 d x

\int sin (10 x) sin (15 x) d x

\frac{d}{d x} (\frac{ln ( x )}{x ^{11}})

What is the limit as x approaches 4 of 2*e^{2/(x-4)} ?
The limit as x approaches 4 of 2*e^{2/(x-4)} is diverges