What is the solution for y^'=(x^3+y^3)/(xy^2) ?

The solution for y^'=(x^3+y^3)/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}

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y^'=(x^3+y^3)/(xy^2)

y^{^{'}} = \frac{x ^{3} + y ^{3}}{x y ^{2}}

Solution steps

y^{'} (x) = \frac{x ^{3} + y ^{3}}{x y ^{2}}

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\frac{d y}{d x} y = 11 x

f (x) = - x^{4} + 4 x^{3} + 8 x^{2} + 5, at x = 2

\frac{d}{d t} (t^{2} + 3 t - 2)

\frac{\partial}{\partial x} (7 e^{8 x})

\frac{\partial}{\partial x} (e^{x y z^{4}})

What is the solution for y^'=(x^3+y^3)/(xy^2) ?
The solution for y^'=(x^3+y^3)/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}