What is the derivative of x-2^{-x} ?

The derivative of x-2^{-x} is 1+ln(2)*2^{-x}

What is the first derivative of x-2^{-x} ?

The first derivative of x-2^{-x} is 1+ln(2)*2^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x - 2^{- x}

1 + ln (2) \cdot 2^{- x}

Solution steps

\frac{d}{d x} (x - 2^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2^{- x})

\frac{d x}{d x} = 1

\frac{d}{d x} (2^{- x}) = - ln (2) \cdot 2^{- x}

= 1 - (- ln (2) \cdot 2^{- x})

Simplify

= 1 + ln (2) \cdot 2^{- x}

\frac{u}{u + \frac{c}{u}}

\int (sin (x + y)) d x

(2 x^{4} - 1) (5 x^{3} + 6 x)

\frac{5}{x}

\frac{d}{d x} (3 x^{3} (x - 2))

What is the derivative of x-2^{-x} ?
The derivative of x-2^{-x} is 1+ln(2)*2^{-x}
What is the first derivative of x-2^{-x} ?
The first derivative of x-2^{-x} is 1+ln(2)*2^{-x}