What is the solution for (dy)/(dx)=(e^x-1)/(e^y) ?

The solution for (dy)/(dx)=(e^x-1)/(e^y) is y=ln(e^x-x+c_{1})

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(dy)/(dx)=(e^x-1)/(e^y)

\frac{d y}{d x} = \frac{e ^{x} - 1}{e ^{y}}

y = ln (e^{x} - x + c_{1})

Solution steps

\frac{d y}{d x} = \frac{e ^{x} - 1}{e ^{y}}

Solve separable ODE:

y = ln (e^{x} - x + c_{1})

y = ln (e^{x} - x + c_{1})

\int_{1}^{4} \frac{x ^{2} - 1}{x} d x

x \to 9 lim (\frac{5 x}{x - 9})

f (x) = ((x^{2} + 7) (5 - x))

\frac{\partial}{\partial x} (e^{x - y})

\frac{x - 4}{x}

What is the solution for (dy)/(dx)=(e^x-1)/(e^y) ?
The solution for (dy)/(dx)=(e^x-1)/(e^y) is y=ln(e^x-x+c_{1})