What is the solution for xy^'-2y=2x^2+2x+2 ?

The solution for xy^'-2y=2x^2+2x+2 is y=2x^2ln(x)-2x-1+c_{1}x^2

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xy^'-2y=2x^2+2x+2

x y^{^{'}} - 2 y = 2 x^{2} + 2 x + 2

y = 2 x^{2} ln (x) - 2 x - 1 + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = 2 x^{2} + 2 x + 2

Solve linear ODE:

y = 2 x^{2} ln (x) - 2 x - 1 + c_{1} x^{2}

y = 2 x^{2} ln (x) - 2 x - 1 + c_{1} x^{2}

g (x) = 3 e^{- 2 x}, (0, 3)

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + x + 1}

\frac{d}{d x} (\frac{1}{3} ln (x))

7 ln (y) y^{^{'}} - x^{9} y = 0

\int sin (2 x) \cdot sec (x) d x

What is the solution for xy^'-2y=2x^2+2x+2 ?
The solution for xy^'-2y=2x^2+2x+2 is y=2x^2ln(x)-2x-1+c_{1}x^2