What is the derivative of tan(bx) ?

The derivative of tan(bx) is sec^2(bx)b

What is the first derivative of tan(bx) ?

The first derivative of tan(bx) is sec^2(bx)b

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\frac{d}{d x} (tan (b x))

sec^{2} (b x) b

Solution steps

\frac{d}{d x} (tan (b x))

Apply the chain rule:

sec^{2} (b x) \frac{d}{d x} (b x)

= sec^{2} (b x) \frac{d}{d x} (b x)

\frac{d}{d x} (b x) = b

= sec^{2} (b x) b

x cos (5 x)

(y + x + \frac{y ^{2}}{x}) d x - x d y = 0

\int 6 sin (x) + 5 d x

\int x 2^{- x} d x

\frac{d y}{d x} = 3 x^{- 4}

What is the derivative of tan(bx) ?
The derivative of tan(bx) is sec^2(bx)b
What is the first derivative of tan(bx) ?
The first derivative of tan(bx) is sec^2(bx)b