What is laplacetransform sin(6(t-(3pi)/6)+3pi) ?

The answer to laplacetransform sin(6(t-(3pi)/6)+3pi) is 6/(s^2+36)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform sin(6(t-(3pi)/6)+3pi)

laplace transform

sin (6 (t - \frac{3 π}{6}) + 3 π)

\frac{6}{s ^{2} + 36}

Solution steps

L {sin (6 (t - \frac{3 π}{6}) + 3 π)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (6 (t - \frac{3 π}{6}) + 3 π)} = \frac{6}{s ^{2} + 6 ^{2}}

= \frac{6}{s ^{2} + 6 ^{2}}

= \frac{6}{s ^{2} + 36}

\frac{d y}{d x} = \frac{e ^{x - y}}{1 + e ^{x}}

\int \frac{x ^{2}}{( x ^{2} - 1 ) ^{\frac{3}{2}}} d x

f (x) = x^{2} - 5 x, at x = - 2

\int 9 x sin (x) cos (x) d x

f (x) = ∣ x ∣ 5 - x^{2}, (2, 2)

What is laplacetransform sin(6(t-(3pi)/6)+3pi) ?
The answer to laplacetransform sin(6(t-(3pi)/6)+3pi) is 6/(s^2+36)