What is the integral of (\sqrt[7]{x^3}) ?

The integral of (\sqrt[7]{x^3}) is 7/10 x^{10/7}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (\sqrt[7]{x^3})

\int (7 x^{3}) d x

\frac{7}{10} x^{\frac{10}{7}} + C

Solution steps

\int 7 x^{3} d x

7 x^{3} = x^{\frac{3}{7}},

assuming

x \geq 0

= \int x^{\frac{3}{7}} d x

Apply the Power Rule

: \frac{7}{10} x^{\frac{10}{7}}

= \frac{7}{10} x^{\frac{10}{7}}

Add a constant to the solution

= \frac{7}{10} x^{\frac{10}{7}} + C

f (r) = \frac{r}{r ^{2} + 7}

\int tan^{2} (\frac{w}{2}) + sec^{2} (\frac{w}{2}) d w

\frac{d}{d x} (sin (3 x) cos (x))

\int (9 x^{2} - 7) d x

\int \frac{- 2 y - 2}{y ^{2} + y} d y

What is the integral of (\sqrt[7]{x^3}) ?
The integral of (\sqrt[7]{x^3}) is 7/10 x^{10/7}+C