What is the integral from-2 to 1 of sqrt(1+25) ?

The integral from-2 to 1 of sqrt(1+25) is 3sqrt(26)

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integral from-2 to 1 of sqrt(1+25)

\int_{- 2}^{1} 1 + 25 d x

326

Decimal

15.29705 \dots

Solution steps

\int_{- 2}^{1} 1 + 25 d x

Integral of a constant:

\int a d x = a x

= [1 + 25 x]_{- 2}^{1}

Simplify

= [26 x]_{- 2}^{1}

Compute the boundaries:

326

= 326

x \to 27 lim (\frac{3 - 3 x}{27 - x})

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\frac{d}{d x} (x (1 - \frac{x}{10}))

\frac{d}{d x} (5 x cos (x^{2}))

What is the integral from-2 to 1 of sqrt(1+25) ?
The integral from-2 to 1 of sqrt(1+25) is 3sqrt(26)