What is the derivative of f(x)=sqrt(1+x^2) ?

The derivative of f(x)=sqrt(1+x^2) is x/(sqrt(1+x^2))

What is the first derivative of f(x)=sqrt(1+x^2) ?

The first derivative of f(x)=sqrt(1+x^2) is x/(sqrt(1+x^2))

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derivative of

f (x) = 1 + x^{2}

\frac{x}{1 + x ^{2}}

Solution steps

\frac{d}{d x} (1 + x^{2})

Apply the chain rule:

\frac{1}{2 1 + x ^{2}} \frac{d}{d x} (1 + x^{2})

= \frac{1}{2 1 + x ^{2}} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= \frac{1}{2 1 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 1 + x ^{2}} \cdot 2 x : \frac{x}{1 + x ^{2}}

= \frac{x}{1 + x ^{2}}

\frac{\partial}{\partial x} (5 arctan (x))

x \to + (- 2) lim (lo g_{2} (8))

\int e^{- x + 1} d x

\int_{- 1}^{2} x - 2 ∣ x ∣ d x

\frac{\partial}{\partial x} (9 + ln (x y - 5))

What is the derivative of f(x)=sqrt(1+x^2) ?
The derivative of f(x)=sqrt(1+x^2) is x/(sqrt(1+x^2))
What is the first derivative of f(x)=sqrt(1+x^2) ?
The first derivative of f(x)=sqrt(1+x^2) is x/(sqrt(1+x^2))