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Popular >

4y^{''}+y^'=0

Solution

4 y^{^{''}} + y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- \frac{t}{4}}

Solution steps

4 y^{''} (t) + y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{t}{4}}

y = c_{1} + c_{2} e^{- \frac{t}{4}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 4y^{''}+y^'=0 ?
The solution for 4y^{''}+y^'=0 is y=c_{1}+c_{2}e^{-t/4}