What is the solution for (dy)/(dx)=(2x+1)/(2y-2) ?

The solution for (dy)/(dx)=(2x+1)/(2y-2) is y=1+sqrt(x^2+x+c_{1)+1},y=1-sqrt(x^2+x+c_{1)+1}

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(dy)/(dx)=(2x+1)/(2y-2)

\frac{d y}{d x} = \frac{2 x + 1}{2 y - 2}

y = 1 + x^{2} + x + c_{1} + 1, y = 1 - x^{2} + x + c_{1} + 1

Solution steps

\frac{d y}{d x} = \frac{2 x + 1}{2 y - 2}

Solve separable ODE:

y = 1 + x^{2} + x + c_{1} + 1, y = 1 - x^{2} + x + c_{1} + 1

y = 1 + x^{2} + x + c_{1} + 1, y = 1 - x^{2} + x + c_{1} + 1

x \to 0 lim (\frac{x}{5 x ^{3} - x ^{4}})

\frac{\partial}{\partial x} (- \frac{y}{( x ^{2} + y ^{2} )})

(x - y) d x = - x d y

- \frac{11}{s ^{6}}

\int_{- 1}^{1} \frac{2 5 - 4 x}{3} d x

What is the solution for (dy)/(dx)=(2x+1)/(2y-2) ?
The solution for (dy)/(dx)=(2x+1)/(2y-2) is y=1+sqrt(x^2+x+c_{1)+1},y=1-sqrt(x^2+x+c_{1)+1}