What is the tangent of y=sqrt(7x+4),(3,5) ?

The tangent of y=sqrt(7x+4),(3,5) is y= 7/10 x+29/10

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tangent of y=sqrt(7x+4),(3,5)

tangent of

y = 7 x + 4, (3, 5)

y = \frac{7}{10} x + \frac{29}{10}

Solution steps

Find the slope of

y = 7 x + 4 : \frac{d y}{d x} = \frac{7}{2 7 x + 4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(3, 5) : y = \frac{7}{10} x + \frac{29}{10}

y = \frac{7}{10} x + \frac{29}{10}

\int_{0}^{1} [x - x^{2}] d x

9 x + 4

x \to - 6 - lim (\frac{- 9 x}{x + 6})

\int_{- \infty}^{0} e^{3 x} d x

\int \frac{1}{u - 1} d u

What is the tangent of y=sqrt(7x+4),(3,5) ?
The tangent of y=sqrt(7x+4),(3,5) is y= 7/10 x+29/10