What is the integral of \sqrt[3]{sqrt(x^5)} ?

The integral of \sqrt[3]{sqrt(x^5)} is 6/11 x^{11/6}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[3]{sqrt(x^5)}

\int 3 x^{5} d x

\frac{6}{11} x^{\frac{11}{6}} + C

Solution steps

\int 3 x^{5} d x

3 x^{5} = 6 x^{5},

assuming

(x^{5}) \geq 0

= \int 6 x^{5} d x

6 x^{5} = x^{\frac{5}{6}},

assuming

x \geq 0

= \int x^{\frac{5}{6}} d x

Apply the Power Rule

: \frac{6}{11} x^{\frac{11}{6}}

= \frac{6}{11} x^{\frac{11}{6}}

Add a constant to the solution

= \frac{6}{11} x^{\frac{11}{6}} + C

h \to 0 lim (- 2 x - h)

x \to 2 lim (\frac{x - 3}{x ^{2} - 4})

\frac{d}{d x} (- 2 sin (x) cos (x) a t [0.2 π])

\frac{18}{( s + 1 ) ^{2} ( s ^{2} + 4 )}

\frac{\partial}{\partial z} (y - z)

What is the integral of \sqrt[3]{sqrt(x^5)} ?
The integral of \sqrt[3]{sqrt(x^5)} is 6/11 x^{11/6}+C