What is (\partial)/(\partial y)(y+xcos(t)) ?

The answer to (\partial)/(\partial y)(y+xcos(t)) is 1

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(\partial)/(\partial y)(y+xcos(t))

\frac{\partial}{\partial y} (y + x cos (t))

1

Solution steps

\frac{\partial}{\partial y} (y + x cos (t))

Treat

x, t

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (x cos (t))

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x cos (t)) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} (\frac{1}{x ^{2} + y ^{2}} + x e^{- y})

5 x^{3} - 4 x^{2} - 11

x \to - 3 - lim (\frac{1}{x + 3})

\frac{d}{d x} (sin (x^{3}) cos^{3} (x))

\int \frac{4}{- 4 x ^{2} - 20 x - 9} d x

What is (\partial)/(\partial y)(y+xcos(t)) ?
The answer to (\partial)/(\partial y)(y+xcos(t)) is 1