What is the integral of sin(z+pi/2) ?

The integral of sin(z+pi/2) is sin(z)+C

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integral of sin(z+pi/2)

\int sin (z + \frac{π}{2}) d z

sin (z) + C

Solution steps

\int sin (z + \frac{π}{2}) d z

Rewrite using trig identities

= \int cos (z) d z

Use the common integral:

\int cos (z) d z = sin (z)

= sin (z)

Add a constant to the solution

= sin (z) + C

\frac{\partial}{\partial x} (8 x z)

(7 - 4) (70)

\int (x + 5) \cdot cos (x) d x

\int sec^{3} (x) sin (x) d x

y^{^{''}} - 4 y^{^{'}} = x - 2