What is the derivative of y=5x^{-7}-8/x ?

The derivative of y=5x^{-7}-8/x is -(35)/(x^8)+8/(x^2)

What is the first derivative of y=5x^{-7}-8/x ?

The first derivative of y=5x^{-7}-8/x is -(35)/(x^8)+8/(x^2)

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derivative of

y = 5 x^{- 7} - \frac{8}{x}

- \frac{35}{x ^{8}} + \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (5 x^{- 7} - \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{- 7}) - \frac{d}{d x} (\frac{8}{x})

\frac{d}{d x} (5 x^{- 7}) = - \frac{35}{x ^{8}}

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= - \frac{35}{x ^{8}} - (- \frac{8}{x ^{2}})

Simplify

= - \frac{35}{x ^{8}} + \frac{8}{x ^{2}}

sin^{2} (4 x)

n = 1 \sum \infty 4^{n} x^{n} n!

n = 1 \sum \infty \frac{ln ( n )}{n}

\int \frac{( 9 x + 14 )}{( x - 2 ) ( x ^{2} + 4 )} d x

\int (2 x + 7)^{3} d x

What is the derivative of y=5x^{-7}-8/x ?
The derivative of y=5x^{-7}-8/x is -(35)/(x^8)+8/(x^2)
What is the first derivative of y=5x^{-7}-8/x ?
The first derivative of y=5x^{-7}-8/x is -(35)/(x^8)+8/(x^2)