What is the integral from 4 to 7 of 1/(sqrt(x-4)) ?

The integral from 4 to 7 of 1/(sqrt(x-4)) is 2sqrt(3)

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integral from 4 to 7 of 1/(sqrt(x-4))

\int_{4}^{7} \frac{1}{x - 4} d x

23

Decimal

3.46410 \dots

Solution steps

\int_{4}^{7} \frac{1}{x - 4} d x

Apply u-substitution

: \int_{0}^{3} 2 d u

= \int_{0}^{3} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{3}

Compute the boundaries:

23

= 23

f (x) = 2 x^{2} + 3

y = e^{\frac{7}{x}}

x \to 0 lim (\frac{x}{ln ( 1 + x )})

\frac{d}{d x} (\frac{cos ( x )}{sin ( x ) + 1})

\frac{d}{d t} (t - \frac{1}{3} t^{3})

What is the integral from 4 to 7 of 1/(sqrt(x-4)) ?
The integral from 4 to 7 of 1/(sqrt(x-4)) is 2sqrt(3)