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Popular >

y^'=9x+y,y(0)=8

Solution

y^{^{'}} = 9 x + y, y (0) = 8

Solution

y = - 9 (x + 1) + 17 e^{x}

Solution steps

y^{'} (x) = 9 x + y

Solve linear ODE:

y = - 9 (x + 1) + 17 e^{x}

y = - 9 (x + 1) + 17 e^{x}

Popular Examples

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\int x^{2} - 6 x d x

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- \frac{1}{3} x^{2}

derivative of ln(9x^2-11)

\frac{d}{d x} (ln (9 x^{2} - 11))

(t cos (t))^{^{'}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=9x+y,y(0)=8 ?
The solution for y^'=9x+y,y(0)=8 is y=-9(x+1)+17e^x