What is the integral from-infinity to-1 of x^{-14/5} ?

The integral from-infinity to-1 of x^{-14/5} is diverges

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integral from-infinity to-1 of x^{-14/5}

\int_{- \infty}^{- 1} x^{- \frac{14}{5}} d x

diverges

Solution steps

\int_{- \infty}^{- 1} x^{- \frac{14}{5}} d x

Compute the indefinite integral:

\int x^{- \frac{14}{5}} d x = - \frac{5}{9 x ^{\frac{9}{5}}} + C

Compute the boundaries:

\int_{- \infty}^{- 1} x^{- \frac{14}{5}} d x =

diverges

= diverges

\int \frac{x + 3}{x ^{2} + 6 x + 1} d x

\int y (2 y^{2} - 3) d y

\frac{d}{d x} (4^{- 2 x})

\frac{d ^{2}}{d x ^{2}} y + 81 y = 0

\frac{d}{d x} (\frac{1 - cosh ( x )}{1 + cosh ( x )})

What is the integral from-infinity to-1 of x^{-14/5} ?
The integral from-infinity to-1 of x^{-14/5} is diverges