What is the solution for (xdy)/(dx)= 1/(y^3) ?

The solution for (xdy)/(dx)= 1/(y^3) is y=\sqrt[4]{4ln(x)+c_{1}},y=-\sqrt[4]{4ln(x)+c_{1}}

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(xdy)/(dx)= 1/(y^3)

\frac{x d y}{d x} = \frac{1}{y ^{3}}

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

Solution steps

\frac{x d y}{d x} = \frac{1}{y ^{3}}

Solve separable ODE:

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

y = 4 4 ln (x) + c_{1}, y = - 4 4 ln (x) + c_{1}

\frac{d y}{d x} = (4 + 3 x)^{4}

\int e^{t x} \cdot \frac{1}{θ} e^{- \frac{x}{θ}} d x

x^{2} y^{^{''}} + 2 x y^{^{'}} - 6 y = 0

x \to - 2 - lim (\frac{1}{( x + 2 ) ^{5}})

\frac{d}{d x} (3 x^{6} e^{x})

What is the solution for (xdy)/(dx)= 1/(y^3) ?
The solution for (xdy)/(dx)= 1/(y^3) is y=\sqrt[4]{4ln(x)+c_{1}},y=-\sqrt[4]{4ln(x)+c_{1}}