What is the tangent of y=3x^2+4x,(-2,4) ?

The tangent of y=3x^2+4x,(-2,4) is y=-8x-12

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tangent of y=3x^2+4x,(-2,4)

tangent of

y = 3 x^{2} + 4 x, (- 2, 4)

y = - 8 x - 12

Solution steps

Find the slope of

y = 3 x^{2} + 4 x : \frac{d y}{d x} = 6 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(- 2, 4) : y = - 8 x - 12

y = - 8 x - 12

\frac{\partial}{\partial x} (2 x y^{7} + x^{8} y^{7})

f (x) = x^{2} + 9

y = (\frac{( x - 2 )}{( x - 3 )})^{2}

f (x) = 5 x + \frac{3}{x}

(4 z + e^{- z^{2}})^{5}

What is the tangent of y=3x^2+4x,(-2,4) ?
The tangent of y=3x^2+4x,(-2,4) is y=-8x-12