What is the limit as x approaches 0 of 1/(1+sin(x)) ?

The limit as x approaches 0 of 1/(1+sin(x)) is 1

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limit as x approaches 0 of 1/(1+sin(x))

x \to 0 lim (\frac{1}{1 + sin ( x )})

1

Solution steps

x \to 0 lim (\frac{1}{1 + sin ( x )})

Plug in the value

x = 0

= \frac{1}{1 + sin ( 0 )}

Simplify

\frac{1}{1 + sin ( 0 )} : 1

= 1

\frac{d h}{d t} = - h

\int \frac{4}{( 2 x + 1 ) ^{3}} d x

\frac{d}{d x} ((x + 1) (x + 2))

x \to 0 lim (x - 8)

\frac{d P}{d t} = - 0.02 P

What is the limit as x approaches 0 of 1/(1+sin(x)) ?
The limit as x approaches 0 of 1/(1+sin(x)) is 1