What is the derivative of (sqrt(x)-2/(\sqrt[3]{x)}) ?

The derivative of (sqrt(x)-2/(\sqrt[3]{x)}) is (sqrt(x)+4)/(6x^{4/3)}

What is the first derivative of (sqrt(x)-2/(\sqrt[3]{x)}) ?

The first derivative of (sqrt(x)-2/(\sqrt[3]{x)}) is (sqrt(x)+4)/(6x^{4/3)}

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\frac{x + 4}{6 x ^{\frac{4}{3}}}

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 2) = \frac{1}{2 x}

Simplify

= \frac{x + 4}{6 x ^{\frac{4}{3}}}

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What is the derivative of (sqrt(x)-2/(\sqrt[3]{x)}) ?
The derivative of (sqrt(x)-2/(\sqrt[3]{x)}) is (sqrt(x)+4)/(6x^{4/3)}
What is the first derivative of (sqrt(x)-2/(\sqrt[3]{x)}) ?
The first derivative of (sqrt(x)-2/(\sqrt[3]{x)}) is (sqrt(x)+4)/(6x^{4/3)}