What is the derivative of (3x^4/5) ?

The derivative of (3x^4/5) is (12x^3)/5

What is the first derivative of (3x^4/5) ?

The first derivative of (3x^4/5) is (12x^3)/5

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\frac{d}{d x} (\frac{3 x ^{4}}{5})

\frac{12 x ^{3}}{5}

Solution steps

\frac{d}{d x} (\frac{3 x ^{4}}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{5} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{5} \cdot 4 x^{4 - 1}

Simplify

\frac{3}{5} \cdot 4 x^{4 - 1} : \frac{12 x ^{3}}{5}

= \frac{12 x ^{3}}{5}

\frac{s}{s ^{2} + 6 s + 10}

y^{^{''}} + 7 y^{^{'}} = 0, y (0) = - 5, y^{^{'}} (0) = - 21

\int 3 x e^{x} d x

\int \frac{1}{16 e ^{- 2 x} + e ^{2 x}} d x

t \to 0 lim (\frac{sin ( k ) t}{t})

What is the derivative of (3x^4/5) ?
The derivative of (3x^4/5) is (12x^3)/5
What is the first derivative of (3x^4/5) ?
The first derivative of (3x^4/5) is (12x^3)/5