What is area f(x)=x^3-x^2-x,g(x)=x ?

The answer to area f(x)=x^3-x^2-x,g(x)=x is 37/12

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area f(x)=x^3-x^2-x,g(x)=x

area

f (x) = x^{3} - x^{2} - x, g (x) = x

\frac{37}{12}

Decimal Notation

3.08333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{2} x^{3} - x^{2} - 2 x d x

Solve

\int_{- 1}^{2} x^{3} - x^{2} - 2 x d x : \frac{37}{12}

The area is:

= \frac{37}{12}

(2 x y^{3} - 3 x^{2} y^{2}) d x + (x y^{3} + 2 x^{2} y^{2}) d y = 0

\frac{d y}{d t} = 0.04 y (400 - y)

\int x - 1 d x

\int \frac{1}{( ( x - 1 ) ( x ^{2} + 1 ) )} d x

y^{^{''}} + 225 y = sec (15 x)

What is area f(x)=x^3-x^2-x,g(x)=x ?
The answer to area f(x)=x^3-x^2-x,g(x)=x is 37/12