What is the derivative of f(x)=x^2-3 ?

The derivative of f(x)=x^2-3 is 2x

What is the first derivative of f(x)=x^2-3 ?

The first derivative of f(x)=x^2-3 is 2x

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derivative of

f (x) = x^{2} - 3

2 x

Solution steps

\frac{d}{d x} (x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= 2 x - 0

Simplify

= 2 x

x^{2} y^{^{'}} = y - x y

\frac{d}{d x} (2 (sin (x^{2}) + 2 x^{2} cos (x^{2})))

\frac{d}{d x} ((x^{10} - 1)^{3})

2000 + 2 x - 0.0001 x^{2}

What is the derivative of f(x)=x^2-3 ?
The derivative of f(x)=x^2-3 is 2x
What is the first derivative of f(x)=x^2-3 ?
The first derivative of f(x)=x^2-3 is 2x