What is the integral from 0 to infinity of 8xe^{2x} ?

The integral from 0 to infinity of 8xe^{2x} is diverges

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integral from 0 to infinity of 8xe^{2x}

\int_{0}^{\infty} 8 x e^{2 x} d x

diverges

Solution steps

\int_{0}^{\infty} 8 x e^{2 x} d x

Compute the indefinite integral:

\int 8 x e^{2 x} d x = 2 (2 e^{2 x} x - e^{2 x}) + C

Compute the boundaries:

\int_{0}^{\infty} 8 x e^{2 x} d x =

diverges

= diverges

\frac{\partial}{\partial x} (7 x^{8} y^{4} + 9 x^{7} y^{6})

\int 2 e^{3 y} d y

\frac{\partial}{\partial z} (x^{2} + 8 z)

x \to 2 lim (\frac{6}{( x - 2 ) ^{2}})

\frac{\partial}{\partial y} (\frac{x - z}{y + z})

What is the integral from 0 to infinity of 8xe^{2x} ?
The integral from 0 to infinity of 8xe^{2x} is diverges