What is (\partial)/(\partial y)(y^2sin(2x)) ?

The answer to (\partial)/(\partial y)(y^2sin(2x)) is 2ysin(2x)

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(\partial)/(\partial y)(y^2sin(2x))

\frac{\partial}{\partial y} (y^{2} sin (2 x))

2 y sin (2 x)

Solution steps

\frac{\partial}{\partial y} (y^{2} sin (2 x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (2 x) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sin (2 x) \cdot 2 y^{2 - 1}

Simplify

= 2 y sin (2 x)

1 - 2^{x}

y = x^{2} (2 x + 3)^{5}

\int \frac{e ^{2 x}}{25 + e ^{4 x}} d x

y = x^{2} 4 x - 7

f (x) = 6 sec (x), at x = \frac{π}{6}

What is (\partial)/(\partial y)(y^2sin(2x)) ?
The answer to (\partial)/(\partial y)(y^2sin(2x)) is 2ysin(2x)