What is the derivative of (3x^2-2^3) ?

The derivative of (3x^2-2^3) is 18x(3x^2-2)^2

What is the first derivative of (3x^2-2^3) ?

The first derivative of (3x^2-2^3) is 18x(3x^2-2)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((3 x^{2} - 2)^{3})

18 x (3 x^{2} - 2)^{2}

Solution steps

\frac{d}{d x} ((3 x^{2} - 2)^{3})

Apply the chain rule:

3 (3 x^{2} - 2)^{2} \frac{d}{d x} (3 x^{2} - 2)

= 3 (3 x^{2} - 2)^{2} \frac{d}{d x} (3 x^{2} - 2)

\frac{d}{d x} (3 x^{2} - 2) = 6 x

= 3 (3 x^{2} - 2)^{2} \cdot 6 x

Simplify

= 18 x (3 x^{2} - 2)^{2}

\frac{d y}{d x} = 6 x (x - 3)

\int \frac{x + 2}{( x ^{2} + 4 x ) ^{2}} d x

4 x - 8

9 - 4 x, at x = - 1

\int_{1}^{4} - 4 e^{x} d x

What is the derivative of (3x^2-2^3) ?
The derivative of (3x^2-2^3) is 18x(3x^2-2)^2
What is the first derivative of (3x^2-2^3) ?
The first derivative of (3x^2-2^3) is 18x(3x^2-2)^2