What is the derivative of (sqrt(s)-4)/(sqrt(s)+2) ?

The derivative of (sqrt(s)-4)/(sqrt(s)+2) is 3/(sqrt(s)(\sqrt{s)+2)^2}

What is the first derivative of (sqrt(s)-4)/(sqrt(s)+2) ?

The first derivative of (sqrt(s)-4)/(sqrt(s)+2) is 3/(sqrt(s)(\sqrt{s)+2)^2}

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derivative of

\frac{s - 4}{s + 2}

\frac{3}{s ( s + 2 ) ^{2}}

Solution steps

\frac{d}{d s} (\frac{s - 4}{s + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d s} ( s - 4 ) ( s + 2 ) - \frac{d}{d s} ( s + 2 ) ( s - 4 )}{( s + 2 ) ^{2}}

\frac{d}{d s} (s - 4) = \frac{1}{2 s}

\frac{d}{d s} (s + 2) = \frac{1}{2 s}

= \frac{\frac{1}{2 s} ( s + 2 ) - \frac{1}{2 s} ( s - 4 )}{( s + 2 ) ^{2}}

Simplify

\frac{\frac{1}{2 s} ( s + 2 ) - \frac{1}{2 s} ( s - 4 )}{( s + 2 ) ^{2}} : \frac{3}{s ( s + 2 ) ^{2}}

= \frac{3}{s ( s + 2 ) ^{2}}

\frac{d}{d x} (arccos (\frac{1}{2} x))

e^{x y} + y^{3} = 2 arcsin (x) + ln (y)

\int (ln (x))^{5} \frac{1}{x} d x

\frac{d y}{d x} + x y = x

f (x) = \frac{1}{4 x ^{2} + 3 x}

What is the derivative of (sqrt(s)-4)/(sqrt(s)+2) ?
The derivative of (sqrt(s)-4)/(sqrt(s)+2) is 3/(sqrt(s)(\sqrt{s)+2)^2}
What is the first derivative of (sqrt(s)-4)/(sqrt(s)+2) ?
The first derivative of (sqrt(s)-4)/(sqrt(s)+2) is 3/(sqrt(s)(\sqrt{s)+2)^2}