What is the integral of 2(x-2)ln(x-2) ?

The integral of 2(x-2)ln(x-2) is x^2ln(x-2)-1/2 x^2+2x-4xln(x-2)+4ln(x-2)-2+C

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integral of 2(x-2)ln(x-2)

\int 2 (x - 2) ln (x - 2) d x

x^{2} ln (x - 2) - \frac{1}{2} x^{2} + 2 x - 4 x ln (x - 2) + 4 ln (x - 2) - 2 + C

Solution steps

\int 2 (x - 2) ln (x - 2) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int (x - 2) ln (x - 2) d x

Expand

(x - 2) ln (x - 2) : x ln (x - 2) - 2 ln (x - 2)

= 2 \cdot \int x ln (x - 2) - 2 ln (x - 2) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int x ln (x - 2) d x - \int 2 ln (x - 2) d x)

\int x ln (x - 2) d x = ln (x - 2) (\frac{1}{2} (x - 2)^{2} + 2 (x - 2)) - \frac{1}{4} (x^{2} + 4 x - 12)

\int 2 ln (x - 2) d x = 2 (x ln (x - 2) - 2 ln (x - 2) - x + 2)

= 2 (ln (x - 2) (\frac{1}{2} (x - 2)^{2} + 2 (x - 2)) - \frac{1}{4} (x^{2} + 4 x - 12) - 2 (x ln (x - 2) - 2 ln (x - 2) - x + 2))

Simplify

2 (ln (x - 2) (\frac{1}{2} (x - 2)^{2} + 2 (x - 2)) - \frac{1}{4} (x^{2} + 4 x - 12) - 2 (x ln (x - 2) - 2 ln (x - 2) - x + 2)) : x^{2} ln (x - 2) - \frac{1}{2} x^{2} + 2 x - 4 x ln (x - 2) + 4 ln (x - 2) - 2

= x^{2} ln (x - 2) - \frac{1}{2} x^{2} + 2 x - 4 x ln (x - 2) + 4 ln (x - 2) - 2

Add a constant to the solution

= x^{2} ln (x - 2) - \frac{1}{2} x^{2} + 2 x - 4 x ln (x - 2) + 4 ln (x - 2) - 2 + C

n = 0 \sum \infty \frac{1}{4 n ^{2} - 1}

\frac{d}{d x} (\frac{3}{4} x^{2})

\int (9 - y^{2})^{2} d y

x \to 0 lim (\frac{3 x ^{5} - 3 x ^{3} + 4 x}{x ^{3} + 6 x ^{2} - 2 x})

\int \frac{- 2 cos ( x )}{sin ^{2} ( x )} d x

What is the integral of 2(x-2)ln(x-2) ?
The integral of 2(x-2)ln(x-2) is x^2ln(x-2)-1/2 x^2+2x-4xln(x-2)+4ln(x-2)-2+C