What is the derivative of (x^2+3x)^2 ?

The derivative of (x^2+3x)^2 is 2(x^2+3x)(2x+3)

What is the first derivative of (x^2+3x)^2 ?

The first derivative of (x^2+3x)^2 is 2(x^2+3x)(2x+3)

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derivative of

(x^{2} + 3 x)^{2}

2 (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x)^{2})

Apply the chain rule:

2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= 2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= 2 (x^{2} + 3 x) (2 x + 3)

\int (3 x^{2} + 4 x) d x

y = x - 1, y = 0, x = 7

x \to \infty lim (e^{x} - 1)

x \to - 7 lim (\frac{x ^{2} - 4}{7 - x})

\int 6 x e^{- 3 x} d x

What is the derivative of (x^2+3x)^2 ?
The derivative of (x^2+3x)^2 is 2(x^2+3x)(2x+3)
What is the first derivative of (x^2+3x)^2 ?
The first derivative of (x^2+3x)^2 is 2(x^2+3x)(2x+3)