What is the limit as x approaches 0 of (x^2-1)/x ?

The limit as x approaches 0 of (x^2-1)/x is diverges

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limit as x approaches 0 of (x^2-1)/x

x \to 0 lim (\frac{x ^{2} - 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{x ^{2} - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x ^{2} - 1}{x}) = - \infty

x \to 0 - lim (\frac{x ^{2} - 1}{x}) = \infty

= diverges

(t^{2} \cdot e^{-, at})

\frac{d}{d x} (x x - x^{2})

\frac{d y}{d x} = \frac{6 y}{5 x}

\int \frac{ln ( x + 2 )}{x + 2} d x

\frac{d}{d x} (\frac{1}{x ^{2} - 3 x})

What is the limit as x approaches 0 of (x^2-1)/x ?
The limit as x approaches 0 of (x^2-1)/x is diverges