What is the integral of (7sec(x)tan(x)+5sec^2(x)) ?

The integral of (7sec(x)tan(x)+5sec^2(x)) is 7sec(x)+5tan(x)+C

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integral of (7sec(x)tan(x)+5sec^2(x))

\int (7 sec (x) tan (x) + 5 sec^{2} (x)) d x

7 sec (x) + 5 tan (x) + C

Solution steps

\int 7 sec (x) tan (x) + 5 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 sec (x) tan (x) d x + \int 5 sec^{2} (x) d x

\int 7 sec (x) tan (x) d x = 7 sec (x)

\int 5 sec^{2} (x) d x = 5 tan (x)

= 7 sec (x) + 5 tan (x)

Add a constant to the solution

= 7 sec (x) + 5 tan (x) + C

\int x^{2} x^{3} + 10 d x

\frac{\partial}{\partial x} (3 y e^{8 x})

\frac{\partial}{\partial x} (2 x - 8 y + 8 x y)

x^{4} + 5 y^{4} \frac{x ^{5} + 4 d y}{d x} = 0

(7, 2), (- 11, - 13)

What is the integral of (7sec(x)tan(x)+5sec^2(x)) ?
The integral of (7sec(x)tan(x)+5sec^2(x)) is 7sec(x)+5tan(x)+C