What is the solution for e^{-12t}f+12e^{-12t}f^'=-4e^{-14t} ?

The solution for e^{-12t}f+12e^{-12t}f^'=-4e^{-14t} is f(t)= 4/(23e^{2t)}+(c_{1})/(e^{t/(12))}

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e^{-12t}f+12e^{-12t}f^'=-4e^{-14t}

e^{- 12 t} f + 12 e^{- 12 t} f^{^{'}} = - 4 e^{- 14 t}

f (t) = \frac{4}{23 e ^{2 t}} + \frac{c _{1}}{e ^{\frac{t}{12}}}

Solution steps

e^{- 12 t} f (t) + 12 e^{- 12 t} f^{'} (t) = - 4 e^{- 14 t}

Solve linear ODE:

f (t) = \frac{4}{23 e ^{2 t}} + \frac{c _{1}}{e ^{\frac{t}{12}}}

f (t) = \frac{4}{23 e ^{2 t}} + \frac{c _{1}}{e ^{\frac{t}{12}}}

6 y^{^{''}} + 18 y^{^{'}} - 24 y = 0

y = \frac{1}{4 x ^{2}}, y = x, y = \frac{x}{16}

\int (12 x + 14) (3 x^{2} + 7 x - 1)^{5} d x

n = 1 \sum \infty \frac{6}{n} - \frac{6}{n + 1}

4 y^{^{''}} - y = 0

What is the solution for e^{-12t}f+12e^{-12t}f^'=-4e^{-14t} ?
The solution for e^{-12t}f+12e^{-12t}f^'=-4e^{-14t} is f(t)= 4/(23e^{2t)}+(c_{1})/(e^{t/(12))}