What is the derivative of x^2-8x+9 ?

The derivative of x^2-8x+9 is 2x-8

What is the first derivative of x^2-8x+9 ?

The first derivative of x^2-8x+9 is 2x-8

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\frac{d}{d x} (x^{2} - 8 x + 9)

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (9) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

\int x cos (6 x^{2}) d x

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y^{^{'}} = (\frac{x ^{2}}{y}), y (1) = 2

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\frac{d}{d x} ((x^{2} - 2 x - 1) (\frac{x + 1}{x + 3}))

What is the derivative of x^2-8x+9 ?
The derivative of x^2-8x+9 is 2x-8
What is the first derivative of x^2-8x+9 ?
The first derivative of x^2-8x+9 is 2x-8