What is the derivative of ln(2x-1+2) ?

The derivative of ln(2x-1+2) is 2/(2x-1)

What is the first derivative of ln(2x-1+2) ?

The first derivative of ln(2x-1+2) is 2/(2x-1)

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\frac{d}{d x} (ln (2 x - 1) + 2)

\frac{2}{2 x - 1}

Solution steps

\frac{d}{d x} (ln (2 x - 1) + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (2 x - 1)) + \frac{d}{d x} (2)

\frac{d}{d x} (ln (2 x - 1)) = \frac{2}{2 x - 1}

\frac{d}{d x} (2) = 0

= \frac{2}{2 x - 1} + 0

Simplify

= \frac{2}{2 x - 1}

\frac{sin ( q ) + cos ( q )}{cos ( q )}

y^{^{''}} - 10 y^{^{'}} + 21 y = 0

\frac{4}{s ( s ^{2} + 2 s + 4 )}

x \to - 8 lim (3 x + 1)

\frac{d}{d x} (cos^{2} (x) + 1)

What is the derivative of ln(2x-1+2) ?
The derivative of ln(2x-1+2) is 2/(2x-1)
What is the first derivative of ln(2x-1+2) ?
The first derivative of ln(2x-1+2) is 2/(2x-1)