What is the tangent of f(x)=tan(x),\at x= pi/3 ?

The tangent of f(x)=tan(x),\at x= pi/3 is y=4x+sqrt(3)-(4pi)/3

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tangent of f(x)=tan(x),\at x= pi/3

tangent of

f (x) = tan (x), at x = \frac{π}{3}

y = 4 x + 3 - \frac{4 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 3)

Find the slope of

f (x) = tan (x) : \frac{df ( x )}{d x} = sec^{2} (x)

Compute the slope of

f (x) = tan (x)

x = \frac{π}{3} : m = 4

Find the line with slope m=

4

and passing through

(\frac{π}{3}, 3) : y = 4 x + 3 - \frac{4 π}{3}

y = 4 x + 3 - \frac{4 π}{3}

\int 3 x^{2} - x d x

\int e^{2 x} cos (3 x) d x

y = \frac{( 5 x ^{2} + 9 )}{x ^{2} + 1}

t \frac{d y}{d t} + t y = 1 - y

y (x^{2} + 1)^{3} \frac{d y}{d x} = x (1 - y^{2})^{2}

What is the tangent of f(x)=tan(x),\at x= pi/3 ?
The tangent of f(x)=tan(x),\at x= pi/3 is y=4x+sqrt(3)-(4pi)/3