What is the solution for y^{'''}+y^{''}+y^'+y=0 ?

The solution for y^{'''}+y^{''}+y^'+y=0 is y=c_{1}e^{-t}+c_{2}cos(t)+c_{3}sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+y^{''}+y^'+y=0

y^{^{'''}} + y^{^{''}} + y^{^{'}} + y = 0

y = c_{1} e^{- t} + c_{2} cos (t) + c_{3} sin (t)

Solution steps

y^{'''} (t) + y^{''} (t) + y^{'} (t) + y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} cos (t) + c_{3} sin (t)

y = c_{1} e^{- t} + c_{2} cos (t) + c_{3} sin (t)

\int_{0}^{7} (50 x + 20) d x

\frac{d}{d x} (sin (π x))

y^{^{''}} + 4 y = 3 sec (2 t)

\int \frac{2 x}{e ^{x^{2} + 2}} d x

\frac{d}{d x} (\frac{128}{x})

What is the solution for y^{'''}+y^{''}+y^'+y=0 ?
The solution for y^{'''}+y^{''}+y^'+y=0 is y=c_{1}e^{-t}+c_{2}cos(t)+c_{3}sin(t)