What is the solution for y^'-4/x y=((y^4))/(x^9) ?

The solution for y^'-4/x y=((y^4))/(x^9) is y=(\sqrt[3]{4}x^4)/(\sqrt[3]{-3x^4+c_{1)}}

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y^'-4/x y=((y^4))/(x^9)

y^{^{'}} - \frac{4}{x} y = \frac{( y ^{4} )}{x ^{9}}

Solution steps

y^{'} (x) - \frac{4}{x} y = \frac{( y ^{4} )}{x ^{9}}

Solve Bernoulli ODE:

\int 3 x^{2} + 3 d x

\frac{d}{d x} (x x + 4)

\frac{d y}{d x} = \frac{x}{7 y}

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What is the solution for y^'-4/x y=((y^4))/(x^9) ?
The solution for y^'-4/x y=((y^4))/(x^9) is y=(\sqrt[3]{4}x^4)/(\sqrt[3]{-3x^4+c_{1)}}