What is (\partial)/(\partial y)(sin(y)cos(x)) ?

The answer to (\partial)/(\partial y)(sin(y)cos(x)) is cos(x)cos(y)

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(\partial)/(\partial y)(sin(y)cos(x))

\frac{\partial}{\partial y} (sin (y) cos (x))

cos (x) cos (y)

Solution steps

\frac{\partial}{\partial y} (sin (y) cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= cos (x) cos (y)

n = 0 \sum \infty \frac{2 ^{n}}{n ^{2}}

f (x) = \frac{2}{3} x - 6

\int \frac{6}{x ^{2} x ^{2} + 36} d x

\int_{1}^{8} 3 x^{2} + \frac{1}{12 x ^{2}} d x

\int \frac{x ^{2}}{( x - 1 ) ^{4}} d x

What is (\partial)/(\partial y)(sin(y)cos(x)) ?
The answer to (\partial)/(\partial y)(sin(y)cos(x)) is cos(x)cos(y)