What is the derivative of f(t)= 1/t ?

The derivative of f(t)= 1/t is -1/(t^2)

What is the first derivative of f(t)= 1/t ?

The first derivative of f(t)= 1/t is -1/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (t) = \frac{1}{t}

- \frac{1}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot t^{- 1 - 1}

Simplify

- 1 \cdot t^{- 1 - 1} : - \frac{1}{t ^{2}}

= - \frac{1}{t ^{2}}

x^{2} + 5 x

x ln (2 x) y^{^{'}} - y = 0

\frac{d}{d x} (c cos (x) + x^{2} sin (x))

(- 4, - 2), (8, 7)

\frac{\partial}{\partial x} (x^{2} e^{3 x y})

What is the derivative of f(t)= 1/t ?
The derivative of f(t)= 1/t is -1/(t^2)
What is the first derivative of f(t)= 1/t ?
The first derivative of f(t)= 1/t is -1/(t^2)