What is the derivative of 7/(4x) ?

The derivative of 7/(4x) is -7/(4x^2)

What is the first derivative of 7/(4x) ?

The first derivative of 7/(4x) is -7/(4x^2)

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\frac{d}{d x} (\frac{7}{4 x})

- \frac{7}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{4} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{4} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{4} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{7}{4} (- 1 \cdot x^{- 1 - 1}) : - \frac{7}{4 x ^{2}}

= - \frac{7}{4 x ^{2}}

y^{^{'}} = \frac{y}{x + y}

\frac{d}{d x} (e^{- 4 x} cos (2 x))

\frac{x ^{3} + 2 x ^{2} - 1}{x + 5}

\int 2 sin (2 x) cos (2 x) d x

\int x sec^{2} (y) d y

What is the derivative of 7/(4x) ?
The derivative of 7/(4x) is -7/(4x^2)
What is the first derivative of 7/(4x) ?
The first derivative of 7/(4x) is -7/(4x^2)