What is the derivative of y= 1/(x-3) ?

The derivative of y= 1/(x-3) is -1/((x-3)^2)

What is the first derivative of y= 1/(x-3) ?

The first derivative of y= 1/(x-3) is -1/((x-3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{1}{x - 3}

- \frac{1}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

= - \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= - \frac{1}{( x - 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x - 3 ) ^{2}}

\int \frac{( x ^{2} + 1 )}{( x - 9 ) ( x - 8 ) ^{2}} d x

\int x cos (8 x^{2}) d x

f (x) = x^{2} - 2 x + 3, at x = 2

x \to 0 lim (Q (x))

\int \frac{7}{3 p - 4} d p

What is the derivative of y= 1/(x-3) ?
The derivative of y= 1/(x-3) is -1/((x-3)^2)
What is the first derivative of y= 1/(x-3) ?
The first derivative of y= 1/(x-3) is -1/((x-3)^2)