What is the derivative of (7x/(x+4)) ?

The derivative of (7x/(x+4)) is (28)/((x+4)^2)

What is the first derivative of (7x/(x+4)) ?

The first derivative of (7x/(x+4)) is (28)/((x+4)^2)

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\frac{d}{d x} (\frac{7 x}{x + 4})

\frac{28}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 x}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{x}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 7 \cdot \frac{\frac{d x}{d x} ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x}{( x + 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 4) = 1

= 7 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}}

Simplify

7 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}} : \frac{28}{( x + 4 ) ^{2}}

= \frac{28}{( x + 4 ) ^{2}}

\int \frac{x ^{3}}{x - 2} d x

\int \frac{8}{x ^{2} + 2} d x

y^{^{''}} - 2 y^{^{'}} + 10 y = 9 e^{t} csc (3 t)

\int \frac{( ln ( x ) ) ^{30}}{x} d x

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 3)

What is the derivative of (7x/(x+4)) ?
The derivative of (7x/(x+4)) is (28)/((x+4)^2)
What is the first derivative of (7x/(x+4)) ?
The first derivative of (7x/(x+4)) is (28)/((x+4)^2)