What is the solution for (dy)/(dx)=(y^2-3y) ?

The solution for (dy)/(dx)=(y^2-3y) is y= 3/(-e^{3x+c_{1)}+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y^2-3y)

\frac{d y}{d x} = (y^{2} - 3 y)

y = \frac{3}{- e ^{3 x + c_{1}} + 1}

Solution steps

\frac{d y}{d x} = (y^{2} - 3 y)

Solve Bernoulli ODE:

y = \frac{3}{- e ^{3 x + c_{1}} + 1}

y = \frac{3}{- e ^{3 x + c_{1}} + 1}

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{3}{2}})

\frac{d}{d x} (- \frac{4}{( x - 2 ) ^{2}})

y^{^{'}} = y^{3}, y (0) = a

\frac{\partial}{\partial x} (e^{x + y^{2}})

\int (x^{8} + 1) d x

What is the solution for (dy)/(dx)=(y^2-3y) ?
The solution for (dy)/(dx)=(y^2-3y) is y= 3/(-e^{3x+c_{1)}+1}