What is the derivative of 2x^3+x+1 ?

The derivative of 2x^3+x+1 is 6x^2+1

What is the first derivative of 2x^3+x+1 ?

The first derivative of 2x^3+x+1 is 6x^2+1

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\frac{d}{d x} (2 x^{3} + x + 1)

6 x^{2} + 1

Solution steps

\frac{d}{d x} (2 x^{3} + x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 6 x^{2} + 1 + 0

Simplify

= 6 x^{2} + 1

\frac{d}{d x} (x + \frac{25}{x})

(ln (\frac{x ( x ^{2} + 1 ) ^{2}}{2 x ^{3} - 1}))^{^{'}}

f (x) = 1 + sin (x), at x = - π

\int x^{3} ln (8 x) d x

x \to - 3 lim (3)

What is the derivative of 2x^3+x+1 ?
The derivative of 2x^3+x+1 is 6x^2+1
What is the first derivative of 2x^3+x+1 ?
The first derivative of 2x^3+x+1 is 6x^2+1