What is the solution for y^'+2/x y=6(y^3)/(x^2) ?

The solution for y^'+2/x y=6(y^3)/(x^2) is y=sqrt((5x)/(12+5c_{1)x^5)},y=-sqrt((5x)/(12+5c_{1)x^5)}

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y^'+2/x y=6(y^3)/(x^2)

y^{^{'}} + \frac{2}{x} y = 6 \frac{y ^{3}}{x ^{2}}

y = \frac{5 x}{12 + 5 c _{1} x ^{5}}, y = - \frac{5 x}{12 + 5 c _{1} x ^{5}}

Solution steps

y^{'} (x) + \frac{2}{x} y = 6 \frac{y ^{3}}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{5 x}{12 + 5 c _{1} x ^{5}}, y = - \frac{5 x}{12 + 5 c _{1} x ^{5}}

y = \frac{5 x}{12 + 5 c _{1} x ^{5}}, y = - \frac{5 x}{12 + 5 c _{1} x ^{5}}

f (x) = 5 x (1 + x^{2})

3 e^{x} x

h \to + 0 - lim (\frac{2 ^{h} - 1}{h})

\int \frac{1}{x ^{2} - 8 x + 25} d x

\frac{d}{d x} (\frac{2 x}{x + 1})

What is the solution for y^'+2/x y=6(y^3)/(x^2) ?
The solution for y^'+2/x y=6(y^3)/(x^2) is y=sqrt((5x)/(12+5c_{1)x^5)},y=-sqrt((5x)/(12+5c_{1)x^5)}